Php Script to identify even or odd

Create form for entering numbers

(condition.html)

<!DOCTYPE html>
<html>
<body bgcolor="orange">
<form method="POST" action="condition.php">
<h1>Enter Number:<input type="number" name="n1" style="width:80%;"><br>
<input type="submit"><br>
</form>
</body>
</html>




(condition.php)

<html>

<body bgcolor="orange">
</html>

<?php
$a=$_POST["n1"];
if($a%2==0)
echo "<h1>Its even number";
else
echo "<h1>Its odd Number";
?>



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